X(3x+2)=3(x^2-4)

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Solution for X(3x+2)=3(x^2-4) equation: 



X(3X+2)=3(X^2-4)

We move all terms to the left:

X(3X+2)-(3(X^2-4))=0

We multiply parentheses

3X^2+2X-(3(X^2-4))=0



We calculate terms in parentheses: -(3(X^2-4)), so:

3(X^2-4)

We multiply parentheses

3X^2-12

Back to the equation:

-(3X^2-12)



We get rid of parentheses

3X^2-3X^2+2X+12=0

We add all the numbers together, and all the variables

2X+12=0

We move all terms containing X to the left, all other terms to the right

2X=-12

X=-12/2

X=-6

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